1 solutions
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0
#include<iostream> using namespace std; int kk(int g) { int sum=0,n=g; while(n>=10) { n=n/10; sum++; } return sum; } int mi(int n) { int sum=1; for(int i=1;i<=n;i++) { sum*=10; } return sum; } int main() { int m,k; cin>>m; for(int i=1;i<=m;i++) { cin>>k; if(k%mi(kk(k))==0) { cout<<0<<endl; } else { cout<<k%mi(kk(k))<<endl; } } return 0; }
简单
- 1
Information
- ID
- 359
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- 10
- Tags
- # Submissions
- 3
- Accepted
- 1
- Uploaded By