1 solutions

  • 0
    @ 2024-10-2 11:15:06
    #include<iostream>
    using namespace std;
    int kk(int g)
    {
        int sum=0,n=g;
        while(n>=10)
        {
            n=n/10;
            sum++;
        }
        return sum;
    }
    int mi(int n)
    {
        int sum=1;
        for(int i=1;i<=n;i++)
        {
            sum*=10;
        }
        return sum;
    }
    int main()
    {
        int m,k;
        cin>>m;
        for(int i=1;i<=m;i++)
        {
            cin>>k;
            if(k%mi(kk(k))==0)
            {
                cout<<0<<endl;
            }
            else
            {
                cout<<k%mi(kk(k))<<endl;
            }
        }
        return 0;
    }
    
    

    简单

    • 1

    Information

    ID
    359
    Time
    1000ms
    Memory
    64MiB
    Difficulty
    10
    Tags
    # Submissions
    3
    Accepted
    1
    Uploaded By