1 solutions

  • 1
    @ 2023-12-30 14:14:02
    #include<iostream>
    #include<string>
    using namespace std;
    int main()
    {
    	string s;
    	getline(cin,s);//输入
    	for(int i=0;i<s.size();i++)
    	{
    		if(s[i]==' ')//为空格时
    		{
    			if(s[i-1]!=' ')//看看是不是多个空格
    			{
    				cout<<' ';//不是就输出
    			}		
    		}
    		else
    		{
    			cout<<s[i];//输出除了空格的字符
    		}
    	}
    	return 0;//完结散花
    }
    
    • 1

    Information

    ID
    332
    Time
    1000ms
    Memory
    64MiB
    Difficulty
    10
    Tags
    # Submissions
    2
    Accepted
    1
    Uploaded By