using namespace std;
int num[25][25],n;
int main(){
	cin>>n;
	num[1][n]=1;//初始为1
	for(int i=1,j=n,tot=1;tot<n*n;){//一直填到n*n个数填完
		while(++i<=n&&!num[i][j])num[i][j]=++tot;--i;//向下
		while(--j> 0&&!num[i][j])num[i][j]=++tot;++j;//向左
		while(--i> 0&&!num[i][j])num[i][j]=++tot;++i;//向上
		while(++j<=n&&!num[i][j])num[i][j]=++tot;--j;//向右
	}
	for(int i=1;i<=n;++i,cout<<endl)for(int j=1;j<=n;++j)
	cout<<num[i][j]<<" ";//输出
	return 0;
}

#include <bits/stdc++.h>
using namespace std;
int a[25][25];
int main(int argc, char **argv){
	int n;
	cin >> n;
	for (int i = 1,j = n,ot = 1;ot <= n * n;){
		while (i <= n && !a[i][j]){
			a[i++][j] = ot++;
		}i--;j--;
//		printf("i:%d j:%d ot:%d ",i,j,ot);
		while (j > 0 && !a[i][j]){
			a[i][j--] = ot++;
		}j++;i--;
//		printf("i:%d j:%d ot:%d ",i,j,ot);
		while (i > 0 && !a[i][j]){
			a[i--][j] = ot++;
		}i++;j++;
//		printf("i:%d j:%d ot:%d ",i,j,ot);
		while (j <= n && !a[i][j]){
			a[i][j++] = ot++;
		}j--;i++;
//		printf("i:%d j:%d ot:%d ",i,j,ot);
	}
	for (int i = 1;i <= n;i++){
		for (int j = 1;j <= n;j++){
			printf("%d ",a[i][j]);
		}
		cout << "\n";
	}
	return 0;
}