8 solutions

  • 7
    @ 2023-10-18 16:20:07

    锻炼还是要有的

    #include <bits/stdc++.h>
    using namespace std;
    struct Node{
    	int data;
    	Node *next;
    };
    Node *head,*p,*r,*s;
    int idx = 0;
    int main(int argc, char **argv){
    	int n,x,a;bool f = 1;
    	head = new Node;
    	r = head;
    	cin >> n;
    	for (int i = 0;i < n;i++){
    		cin >> a;
    		p = new Node;
    		p -> data = a;
    		p -> next = NULL;
    		r -> next = p;
    		r = p;
    	}
    	p = head -> next;
    	cin >> x;
    	if(x == 1){
    		p = head -> next -> next;
    		for (int i = 0;i < n - 1;i++){
    			cout << p -> data << ' ';
    			p = p -> next;
    		}
    		// cout << p -> data;
    		return 0;
    	}
    	while (idx < x - 2){
    		p = p -> next;
    		idx++;
    	}
    	if(p -> next == NULL){
    		f = 0;
    		p = head -> next;
    	}else{
    		s = p -> next;
    		p -> next = p -> next -> next;
    		delete s;
    		p = head -> next;
    	}
    	while (p -> next != NULL){
    		cout << p -> data << ' ';
    		p = p -> next;
    	}
    	if (f)	cout << p -> data;
    	return 0;
    }
    

    花了好久才做出来,点个赞吧❤

    • 1
      @ 2024-11-29 21:08:26

      思路(乱七八糟)

      用链表存一个数组,删除一个内容(欸,数组......)
      用一个struct存节点,插入节点后,由于1和2比较特殊(1:为头,2:头后第一个,在for循环中判断不到),进行特判。

      呆码

      #include<bits/stdc++.h>
      using namespace std;
      struct Node{
      	int n;
      	Node* next; 
      }*front=new Node;
      int main(){
      	int n;
      	cin>>n;
      	Node *x,*p=NULL;
      	x=front;
      	for(int i=0;i<n;i++){
      		p=new Node;
      		int www;
      		cin>>www;
      		p->n=www;
      		p->next=NULL;
      		x->next=p;
      		x=p;
      	}
      	int c;
      	cin>>c;
      	if(c==1){//1的特判
      		Node* a=front->next->next;
      		for(int i=2;i<=n;i++){
      			cout<<a->n<<" ";
      			a=a->next;
      		}
      		return 0;
      	}
      	if(c==2){//2的特判
      		Node* a=front->next;
      			cout<<a->n<<" ";
      			a=a->next;
      			a=a->next;
      			for(int i=3;i<=n;i++){
      			cout<<a->n<<" ";
      			a=a->next;
      		}
      		return 0;
      	}
      	Node* a=front->next;
      	for(int i=1;i<n;i++){//其他情况
      		cout<<a->n<<" ";
      		a=a->next;
      		if(i==c-2)a->next=a->next->next;
      	}
      }
      

      完成后突然发现,h1表体好像有些太显眼......
      幼稚题解,必须点赞

      • 0
        @ 2025-3-19 17:58:07

        非常链表

        #include <iostream>
        #include <cstdio>
        using namespace std;
        
        
        
        int n,m,cnt,x,index;
        struct Node{
        	int next;//下一个结点 
        	int mine;//结点自己 
        }arr[11];
        
        int main(){
        
        	scanf("%d",&n);
        	for(int i = 1;i <= n;i++){
        		scanf("%d",&cnt);
        		arr[i].mine = cnt;
        		arr[i - 1].next = i;//标记下一个 
        	} 
        
        	scanf("%d",&m);//输入删除位置 
        
        	arr[m - 1].next++;//更改指针 
        
        	for(int i = 1;i < n;i++){
        		int index = arr[x].next;//指针为下一个结点 
        		printf("%d ",arr[index].mine);//输出下一个 
        		x = index; 
        	}
        	return 0;
        }
        
        

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        • -1
          @ 2024-11-29 20:52:40
          #include<bits/stdc++.h>
          using namespace std;
          int n,x,c;
          struct Node{
          	int data;
          	Node* next;
          }; 
          int main(){
          	Node* head;
          	cin >>n;
          	Node* ptr=new Node;
          	head=ptr;
          	for(int i=1;i<=n;i++){
          		ptr->next=new Node;
          		ptr=ptr->next;
          		cin >>c;
          		ptr->data=c;
          		ptr->next=NULL;
          	}
          	cin>>x; 
          	ptr=head;
          	for(int i=1;i<=x-1;i++){
          		ptr=ptr->next;
          	}
          	ptr->next=ptr->next->next; 
          	ptr=head->next;
          	while(ptr!=NULL){
          		cout <<ptr->data<<" ";
          		ptr=ptr->next;
          	}
          	return 0;//别抄我的QAQ
          }
          
          • @ 2024-11-29 20:57:51

            各位都去给@c24kongxiangtai点小心心,快去!!千万别点踩!!!!!!

        • -1
          @ 2023-10-13 19:23:34

          666

          using namespace std;
          int arr[110];
          int main(){
          	int n;
          	cin>>n;
          	for(int i=0;i<n;i++)
          		cin>>arr[i];
          	int x;
          	cin>>x;
          	for(int i=0;i<n;i++) if(arr[i]!=x) cout<<arr[i]<<' ';
          	return 0;
          }
          
          • -2
            @ 2023-10-4 11:14:21
            ```
            #include <iostream> 
            using namespace std; 
            int main() { 
            int n,m; 
            cin>>n; 
            int a[n+1]; 
            for(int i=1;i<=n;i++) { 
            cin>>a[i]; 
            } 
            cin>>m; 
            int b[n+1]; 
            for(int i=1;i<=n;i++) { 
            if(i!=m) b[i]=a[i]; 
            else break;
            
            }
            for(int i=m;i<n;i++)
            {
            	b[i]=a[i+1];
            }
            for(int i=1;i<n;i++)
            {
            	cout<<b[i]<<" ";
            }
            }
            
            
            ```
            
            ```
            • -9
              @ 2023-10-5 11:51:03

              #include using namespace std; int main(){ int n,x,m; cin>>n; int a[n+1]; for( int i=1;i<=n;++i) cin>>a[i] ; cin>>x;

              for(int i=x;i<=n;i++){ a[i]=a[i+1]; }

              for( int i=1;i<=n-1;++i)
              cout<<a[i]<<" ";
              

              }

              • -10
                @ 2023-10-3 11:08:14

                #include using namespace std; int main() { int n,m; cin>>n; int a[n+1]; for(int i=1;i<=n;i++) { cin>>a[i]; } cin>>m; int b[n+1]; for(int i=1;i<=n;i++) { if(i!=m)b[i]=a[i]; else break;

                }
                for(int i=m;i<n;i++)
                {
                	b[i]=a[i+1];
                }
                for(int i=1;i<n;i++)
                {
                	cout<<b[i]<<" ";
                }
                

                }

                • 1

                Information

                ID
                226
                Time
                1000ms
                Memory
                64MiB
                Difficulty
                7
                Tags
                # Submissions
                164
                Accepted
                36
                Uploaded By