1 solutions

  • 0
    @ 2024-10-25 21:13:38
    #include <bits/stdc++.h>
    using namespace std;
    int arr[2010];
    int main(){
    	int n;
    	cin>>n;
    	arr[1]=0;
    	arr[2]=1;
    	arr[3]=1;
    	for(int i=4;i<=2000;i++) arr[i]=arr[i-1]+arr[i-2];
    	cout<<arr[n];
    	return 0;
    }//空间换时间
    
    • 1

    Information

    ID
    216
    Time
    1000ms
    Memory
    256MiB
    Difficulty
    10
    Tags
    # Submissions
    4
    Accepted
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