2 solutions

  • 1
    @ 2024-11-16 14:19:59

    P1980 C++

    #include<bits/stdc++.h>
    using namespace std;
    int n1,n2;
    int cnt=0;
    int cot(int n,int m){
    	int cntr=0;
    	while(n!=0){
    		if(n%10==m){
    			cntr++;
    		}
    		n/=10;
    	}
    	return cntr;
    }
    int main(){
    	cin>>n1>>n2;
    	for(int i=1;i<=n1;i++){
    		cnt+=cot(i,n2);
    	}
    	cout<<cnt;
    	return /*164*/0;
    }
    
    • 1
      @ 2024-11-10 17:20:45
      #include<bits/stdc++.h>
      #define Goose main 
      using namespace std;
      #define qUark int
      #define g ;
      #define QUARK return
      #define Quark cin
      #define quarK cout
      #define qq >>
      #define kk <<
      #define quArk for
      #define quaRk while
      #define QUark if
      #define ss {
      #define ee }
      #define aa (
      #define rr )
      qUark n,x,ans=0 g
      qUark Goose aa rr ss
      	Quark qq n qq x g
      	quArk aa qUark i=1 g i<=n g i++ rr ss
      		qUark k=i g
      		quaRk aa k rr ss
      			QUark aa k%10==x rr ans++ g
      			k/=10 g
      		ee
      	ee
      	quarK kk ans kk "\n" g
      	QUARK 0 g
      ee
      

      Goose语言精选代码(保a)

      • 1

      Information

      ID
      1131
      Time
      1000ms
      Memory
      125MiB
      Difficulty
      3
      Tags
      # Submissions
      25
      Accepted
      19
      Uploaded By