1 solutions
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1
#include<iostream> using namespace std; int main() { int n,s1=0,s2=0; char a,b; cin>>n; for(int i=1;i<=n;i++) { cin>>a>>b; if(a=='J') { if(b=='B') { s1++; } else if(b=='S') { s2++; } } else if(a=='S') { if(b=='J') { s1++; } else if(b=='B') { s2++; } } else if(a=='B') { if(b=='S') { s1++; } else if(b=='J') { s2++; } } } if(s1>s2) { cout<<"xiaoyan"; } else if(s1==s2) { cout<<"QAQ"; } else { cout<<"xiaoke"; } return 0; }
简单
- 1
Information
- ID
- 97
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- 10
- Tags
- # Submissions
- 5
- Accepted
- 1
- Uploaded By