1 solutions
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#include<bits/stdc++.h> using namespace std; int main() { bool flag=false; string a,b; cin>>a>>b; if((a[a.size()-1]=='0')||(a[a.size()-1]=='5')||(b[b.size()-1]=='0')||(b[b.size()-1]=='5')) { flag=true; } if(flag==true) { cout<<"Yes"; } else { cout<<"No"; } return 0; }//听我的!不开string见祖宗!
- 1
Information
- ID
- 36
- Time
- 1000ms
- Memory
- 64MiB
- Difficulty
- 10
- Tags
- # Submissions
- 9
- Accepted
- 1
- Uploaded By