1 solutions
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1
#include<bits/stdc++.h> using namespace std; long t,n; long a[105],b[105]; int main(){ cin>>t; for(int i=0;i<t;i++){ long ma=-1; cin>>n; for(int j=0;j<n;j++){ cin>>a[j]>>b[j]; if(a[j]<=10) ma=max(ma,b[j]); } for(int j=0;j<n;j++) if(b[j]==ma) cout<<j+1<<endl; } return 0; }
- 1
Information
- ID
- 913
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 7
- Tags
- (None)
- # Submissions
- 36
- Accepted
- 9
- Uploaded By