1 solutions
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0
#include<iostream> using namespace std; int dp[105][105]; int main() { int n,m; while(cin>>n>>m) { for(int i=1;i<=n;i++) { for(int j=1;j<=m;j++) { dp[i][j]=i; } } for(int i=1;i<=n;i++) { for(int k=1;k<=i;k++) { for(int j=2;j<=m;j++) { dp[i][j]=min(dp[i][j],max(dp[k-1][j-1],dp[i-k][j])+1); } } } cout<<dp[n][m]<<endl; } return 0; }
- 1
Information
- ID
- 785
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 6
- Tags
- # Submissions
- 25
- Accepted
- 11
- Uploaded By