1 solutions
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#include<iostream> #include<cstdio> #include<cstring> #include<algorithm> using namespace std; const int N=105; int a[N],f[N][N]; int main(){ int n; cin>>n; for(int i=1;i<=n;i++){ scanf("%d",&a[i]); a[i]+=a[i-1]; } memset(f,127,sizeof(f)); for(int i=1;i<=n;i++)f[i][i]=0; for(int i=n-1;i>0;i--){ for(int j=i+1;j<=n;j++){ for(int k=i;k<j;k++){ f[i][j]=min(f[i][j],f[i][k]+f[k+1][j]+a[j]-a[i-1]); } } } cout<<f[1][n]; return 0; }
- 1
Information
- ID
- 759
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 7
- Tags
- # Submissions
- 16
- Accepted
- 11
- Uploaded By