2 solutions

  • 5
    @ 2024-1-23 10:46:53
    #include<bits/stdc++.h>
    using namespace std;
    int n,k;
    void d(int n,int k){
    	cout<<int(n/pow(10,k)*10)%10<<endl;
    }
    int main(){
    	cin>>n>>k;
    	d(n,k);
    	return 0;
    }
    

    简单

    • 0
      @ 2023-11-16 13:20:44
      #include<iostream>
      using namespace std;
      void digit(int n,int k){
      	int ans=1;
      	for(int i=1;i<k;i++)ans*=10;
      	cout<<n/ans%10;
      }
      int main(){
      	int n;
      	int k;
      	cin
      	>>n
      	>>k;
      	digit(n,k);
      }
      
      • 1

      Information

      ID
      650
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      4
      Tags
      # Submissions
      31
      Accepted
      18
      Uploaded By