#include<bits/stdc++.h>
using namespace std;
int n;
string a,b;
int turn(string x){
	switch(x.size()){
		case 4:return 1;//石头 
		case 8:return 2;//剪刀 
		case 5:return 3;//布 
	}
}
int main(){
	cin>>n;
	for(int i=0;i<n;i++){
		cin>>a>>b;
		int x=turn(a);
		int y=turn(b);
		switch(x-y){
			case 0:cout<<"Tie"<<endl;break;
			case -1:
			case 2:cout<<"Player1"<<endl;break;
			case -2:
			case 1:cout<<"Player2"<<endl;break;
		}
	}
	return 0;
}

提供一种转换的思路 代码稍长但是不枯燥

明明15行就能搞定

#include<bits/stdc++.h>
using namespace std;
int main(){
	int n;cin>>n;
	for(int i=0;i<n;i++){
		string a,b;
		cin>>a>>b;
		if(a[0]==b[0])cout<<"Tie\n";
		else if(a[0]==83&&b[0]==80)cout<<"Player1\n";
		else if(a[0]==80&&b[0]==83)cout<<"Player2\n";
		else if(a[0]<b[0])cout<<"Player1\n";
		else cout<<"Player2\n";
	}
	return 0;
}

#include<iomanip>
#include<string>
using namespace std;
int main(){
string a,b;
int n;
cin>>n;
for(int i=0;i<n;i++){
cin>>a>>b;
if(a==b)cout<<"Tie"<<endl;
else{
if(a=="Rock"){
if(b=="Scissors")cout<<"Player1"<<endl;
else cout<<"Player2"<<endl;
}if(a=="Paper"){
if(b=="Rock")cout<<"Player1"<<endl;
else cout<<"Player2"<<endl;
}if(a=="Scissors"){
if(b=="Paper")cout<<"Player1"<<endl;
else cout<<"Player2"<<endl;
}
}
}
}

`

#include<bits/stdc++.h>
using namespace std;
int main() {
	int n;
	cin>>n;
	for(int i=0; i<n; i++) {
		string a,b;
		cin>>a>>b;//读入两个字符串
		if(a[0]==b[0])cout<<"Tie\n";//首位相同，平局
		else if(a[0]=='R') {
			if(b[0]=='P')cout<<"Player2\n";
			else cout<<"Player1\n";
		}
		else if(a[0]=='P') {
			if(b[0]=='S')cout<<"Player2\n";
			else cout<<"Player1\n";
		}
		else if(a[0]=='S') {
			if(b[0]=='R')cout<<"Player2\n";
			else cout<<"Player1\n";
		}//以上是逐个判断，按照 Player1 的情况分类讨论
		//因为讨论过平局了，可以只分两种情况考虑
		//记得使用 else-if
	}
	return 0;
}