2 solutions
-
4
#include<bits/stdc++.h> using namespace std; double m,n; double k=0; int a[105][105],b[105][105]; int main(){ cin>>m>>n; for(int i=0;i<m;i++) for(int j=0;j<n;j++) cin>>a[i][j]; for(int i=0;i<m;i++) for(int j=0;j<n;j++){ cin>>b[i][j]; if(b[i][j]==a[i][j]) k++; } cout<<fixed<<setprecision(2)<<k/m/n*100<<endl; return 0; }
-
0
``` ``` ``` ``` #include <iostream> #include <iomanip> using namespace std; int main(){ int m , n; int a = 0; cin >> m >> n; int x[m][n] , y[m][n]; for(int i = 0;i < m;i++){ for(int j = 0;j < n;j++){ cin >> x[i][j]; } } for(int i = 0;i < m;i++){ for(int j = 0;j < n;j++){ cin >> y[i][j]; } } for(int i = 0;i < m;i++){ for(int j = 0;j < n;j++){ if(x[i][j] == y[i][j]){ a++; } } } cout << fixed << setprecision(2) << (a * 100.0) / (m * n) << endl; return 0; }`
- 1
Information
- ID
- 609
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 3
- Tags
- # Submissions
- 27
- Accepted
- 20
- Uploaded By