8 solutions

  • 2
    @ 2023-10-28 21:16:56

    根本不用数组

    #include<iostream>
    using namespace std;
    int main()
    {
     int n,ma=0,s=0;
     cin>>n;//输入
     int x;
     for(int i=0;i<n;i++)
     {
      cin>>x;//输入
      if(x>ma)//是否是最大值
       ma=x;//更新
      s+=x;//总和
     }
     cout<<s-ma;//减掉最大值
     return 0;//完结散花!
    }
    
    • 1
      @ 2024-2-3 13:04:34
      #include<bits/stdc++.h>
      using namespace std;
      int a[10001];
      
      int main () {
      	int n,maxx=INT_MIN,sum=0; cin >> n;
      	for (int i = 1; i <= n; i++) {
      		cin >> a[i];
      		maxx = maxx<a[i]?a[i]:maxx;
      	}
      	for (int i = 1; i <= n; i++) {
      		sum += maxx==a[i]?0:a[i];
      	}
      	cout << sum;
      	return 0;
      }
      
      • 0
        @ 2024-9-12 21:41:07
        #include<queue>
        #include<stack>
        #include<cmath>
        #include<algorithm>
        #include<cstring>
        using namespace std; 
        int main()
        {
        	int a;
        	cin>>a;
        	int b[200];
        	int i=0;
        	int n=a;
        	int sum=0;
        	while(n--)
        	{
        		cin>>b[i];
        		i++;//i++在后面😶‍🌫️
        	}
        	sort(b,b+a);//见#A1112. 最大值和最小值的差
        	n=a;
        	i=0;
        	while(n--)
        	{
        		if(b[i]<b[a-1])
        		{
        			sum+=b[i];
        		}
        		i++;//i++还是在后面哦!
        	}
        	cout<<sum;
            return 0;
        
        }
        
        

        不要抄哦( •̀ ω •́ )y!!

        • 0
          @ 2024-7-17 17:40:21

          No数组

          #include<bits/stdc++.h>
          using namespace std;
          int main() {
              int a,n,max=(-99999999),sum=0;
              cin>>n;
              for(int i=1;i<n+1;i++){
              cin>>a;
          	sum+=a;
          	if(max<a)
          	max=a;
          	}
          	cout<<sum-max;
          	return 0;
          }
          
          • 0
            @ 2023-10-3 11:11:40

            #include<bits/stdc++.h> using namespace std;

            int main(){ int n,maxn,sum=0; cin>>n; const int N=n; int a[N]; for(int i=0;i<N;i++){ cin>>a[i]; } maxn=a[0]; for(int j=0;j<N;j++){ maxn=max(maxn,a[j]); } for(int k=0;k<N;k++){ if(a[k]!=maxn){ sum+=a[k]; } else{ sum+=0; } } cout<<sum; return 0; }

            • 0
              @ 2023-9-9 16:05:42

              两个for应该是最简的(吧?)

              #include<iostream>
              using namespace std;
              int n,ma=0,s=0;
              int a[1005];
              int main(){
              	cin>>n;
              	for(int i=0;i<n;i++){
              		cin>>a[i];
              		ma=max(ma,a[i]);
              	}
              	for(int i=0;i<n;i++) if(a[i]!=ma) s+=a[i];
              	cout<<s<<endl;
              	return 0;
              }
              
              
            • -1
              @ 2023-9-27 14:02:07
              #include <bits/stdc++.h>
              using namespace std;
              int main(int argc, char **argv){
              	int n,a[105],mx = -1000005,sum = 0;
              	cin >> n;
              	for (int i = 0;i < n;i++){
              		cin >> a[i];
              		mx = max(mx,a[i]);
              	}
              	for(int i = 0;i < n;i++){
              		if (a[i] != mx){
              			sum+= a[i];
              		}
              	}
              	cout << sum;
              	return 0;
              }
              
              • -1
                @ 2023-9-21 22:37:21
                #include <iostream>
                #include <algorithm>
                using namespace std;
                int n,m,ans=0,a[10005];
                int main(){
                	cin>>n;
                	for(int i=1;i<=n;i++) cin>>a[i];
                	sort(a+1,a+n+1);
                	for(int i=1;i<=n;i++){
                		if(a[i]<a[n]) ans+=a[i];
                		else break;
                	}
                	cout<<ans;
                	return 0;
                }
                
                • 1

                Information

                ID
                599
                Time
                1000ms
                Memory
                256MiB
                Difficulty
                1
                Tags
                # Submissions
                90
                Accepted
                63
                Uploaded By