8 solutions

  • 1
    @ 2024-1-27 11:48:16
    #include<iostream>
    
    using namespace std;
    long n,x,s=0;
    int main(){
    	cin>>n;
    	int a[n];
    	for(int i=0;i<n;i++) cin>>a[i];
    	cin>>x;
    	for(int i=0;i<n;i++){
    		if(a[i]==x) s++;
    	}
    	cout<<s;
    	return 0;
    }
    
    • 0
      @ 2025-1-30 11:42:45
      //桶排
      #include<bits/stdc++.h>
      using namespace std;
      int l[255555],a;
      short n;
      int main(){
         cin>>n;
         for(int i=1;i<=n;i++){
            cin>>a;
            l[a]++;}
         cin>>n;
         cout<<l[n];
         return 0;
      }
      
      • 0
        @ 2024-9-13 19:21:22
        #include<iostream>
        using namespace std;
        int main (){
            int a[99],b,sum=0,c;
            cin>>b;
            int d=b;
            while(d--)cin>>a[d];
        	cin>>c; 
            while(b--)if(a[b]==c)sum++;
            cout<<sum;
            return 0;
        }
        

        短小精悍1.0 不要抄哦!还是有坑

        • 0
          @ 2024-9-13 19:15:07
          #include<queue>
          #include<stack>
          #include<cmath>
          #include<algorithm>
          #include<cstring>
          using namespace std;   
          int main ()
          {
              int a[99];
              int b,sum=0,c;
              cin>>b;
              int d=b;
              while(d--)
              {
              	cin>>a[d];//输出
          	}
          	cin>>c; 
              while(b--)//遍历数组
              {
                  if(a[b]==c)
                  {
                      sum++;
                  }
              }
              cout<<sum;//输出
              return 0;
          }
          
          

          不要抄哦!有坑

          • 0
            @ 2024-8-7 11:28:07
            #include<iostream>
            #include<cmath>
            using namespace std;
            int a[101],n,m,sum=0;
            int main() {
            	cin>>n;
            	for(int i=0;i<n;++i)
            	{
            	cin>>a[i];
            	}
            	cin>>m;
            	for(int j=0;j<n;++j)
            	{
            	if(a[j]==m)
            		sum++;
            	}
            	cout<<sum;
            	return 0;
            }
            
            • 0
              @ 2023-10-3 10:41:08

              #include<bits/stdc++.h> using namespace std;

              int main(){ int N,m,sum=0; cin>>N; const int n=N; int a[n]; for (int i=0;i<=n-1;i++){ cin>>a[i]; } cin>>m; for(int j=0;j<=n-1;j++){ if(a[j]==m){ sum+=1; } } cout<<sum; return 0; }

              • 0
                @ 2023-9-21 22:26:24
                #include <iostream>
                using namespace std;
                int n,m,ans=0;
                int main(){
                	cin>>n;
                	int a[n]={0};
                	for(int i=1;i<=n;i++) cin>>a[i];
                	cin>>m;
                	for(int i=1;i<=n;i++){
                		if(a[i]==m) ans++;
                	}
                	cout<<ans<<endl;
                	return 0;
                }
                
                • -1
                  @ 2023-9-27 13:23:11
                  #include <bits/stdc++.h>
                  using namespace std;
                  int main(int argc, char **argv){
                  	int n,a[105],m,cnt = 0;
                  	cin >> n;
                  	for (int i = 0;i < n;i++){
                  		cin >> a[i];
                  	}
                  	cin >> m;
                  	for (int i = 0;i < n;i++){
                  		if (a[i] == m){
                  			cnt++;
                  		}
                  	}
                  	cout << cnt;
                  	return 0;
                  }
                  
                  • 1

                  Information

                  ID
                  588
                  Time
                  1000ms
                  Memory
                  256MiB
                  Difficulty
                  3
                  Tags
                  # Submissions
                  117
                  Accepted
                  67
                  Uploaded By