5 solutions
- 1
Information
- ID
- 559
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- # Submissions
- 41
- Accepted
- 33
- Uploaded By
水
#include <bits/stdc++.h>
using namespace std;
int main()
{
int n;
double ans;
cin >> ans;
cin >> n;
for(int i = 1; i <= n; i++)
{
ans*=1.001;
}
printf("%.4f", ans);
return 0;
}
//水题一道
#include<bits/stdc++.h>
using namespace std;
int main(){
double n;
int m;
cin>>n>>m;
for(int i=1;i<=m;i++) n=n+n*0.001;
printf("%.4f",n);
return 0;
}
#include using namespace std; int main() { long long x,n; cin>>x>>n; double s=x; for(int i=1;i<=n;i++) { s*=(1+0.001); } printf("%.4f",s); }
By signing up a ZXOJ universal account, you can submit code and join discussions in all online judging services provided by us.