3 solutions

  • 3
    @ 2023-9-16 16:23:46
    #include <iostream>
    using namespace std;
    int n,a[20][20];
    int main(){
    	cin>>n;
    	for(int i=1;i<=n;i++) cin>>a[0][i]>>a[1][i]>>a[2][i];
    	int cnt1=0,cnt2=0,cnt3=0;
    	for(int i=1;i<=n;i++){
    		cnt1+=a[0][i];
    		cnt2+=a[1][i];
    		cnt3+=a[2][i];
    	}
    	cout<<cnt1<<" "<<cnt2<<" "<<cnt3<<" "<<cnt1+cnt2+cnt3<<endl;
    	return 0;
    }
    
    • 1
      @ 2023-9-23 18:44:38

      #include<bits/stdc++.h> using namespace std; int main(){ double a,b,c,d,z1=0,z2=0,z3=0; cin>>a; for(int i=1;i<=a;i++){ cin>>b>>c>>d; z1+=b; z2+=c; z3+=d; } cout<<z1<<" "<<z2<<" "<<z3<<" "<<z1+z2+z3; }

      • 0
        @ 2023-9-16 16:23:39
        #include <iostream>
        using namespace std;
        int n,a[20][20];
        int main(){
        	cin>>n;
        	for(int i=1;i<=n;i++) cin>>a[0][i]>>a[1][i]>>a[2][i];
        	int cnt1=0,cnt2=0,cnt3=0;
        	for(int i=1;i<=n;i++){
        		cnt1+=a[0][i];
        		cnt2+=a[1][i];
        		cnt3+=a[2][i];
        	}
        	cout<<cnt1<<" "<<cnt2<<" "<<cnt3<<" "<<cnt1+cnt2+cnt3<<endl;
        	return 0;
        }
        
        • 1

        Information

        ID
        552
        Time
        1000ms
        Memory
        256MiB
        Difficulty
        1
        Tags
        # Submissions
        48
        Accepted
        34
        Uploaded By