6 solutions
- 1
Information
- ID
- 523
- Time
- 1000ms
- Memory
- 256MiB
- Difficulty
- 1
- Tags
- # Submissions
- 74
- Accepted
- 57
- Uploaded By
#include #include using namespace std;
int main() { long long a, b; cin >> a >> b; cout << a * b << endl;
return 0;
}
#include <bits/stdc++.h>
using namespace std;
int a,b;
int main(){
cin>>a;
cin>>b;
cout<<a*b;
return 0;}
#include<bits/stdc++.h>
#define ll long long
using namespace std;
ll a,b;
int main(){
cin>>a>>b;
cout<<a*b<<"\n";
return 0;
}
最短写法:
#include<iostream>
using namespace std;int main(){int a,b;cin>>a>>b;cout<<a*b;return 0;}
#include <bits/stdc++.h>
using namespace std;
int a,b;
int main(){
cin>>a;
cin>>b;
cout<<a*b;
return 0;
}//不用double的。
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