6 solutions

  • 1
    @ 2024-1-27 11:28:02
    
    

    #include #include using namespace std;

    int main() { long long a, b; cin >> a >> b; cout << a * b << endl;

    return 0;
    

    }

    
    
    • 1
      @ 2024-1-27 11:27:28
      
      

      #include #include using namespace std;

      int main() { long long a, b; cin >> a >> b; cout << a * b << endl;

      return 0;
      

      }

      
      
      • -1
        @ 2023-12-22 21:25:52
        #include <bits/stdc++.h>
        using namespace std;
        int a,b;
        int main(){
            cin>>a;
            cin>>b;
            cout<<a*b;
            return 0;}
        
        • -2
          @ 2024-1-26 9:53:21
          #include<bits/stdc++.h>
          #define ll long long
          using namespace std;
          ll a,b;
          int main(){
          	cin>>a>>b;
          	cout<<a*b<<"\n";
          	return 0;
          }
          
          • -2
            @ 2023-10-29 13:41:07

            最短写法:

            #include<iostream>
            using namespace std;int main(){int a,b;cin>>a>>b;cout<<a*b;return 0;}
            
            • -2
              @ 2023-10-5 14:40:03
              #include <bits/stdc++.h>
              using namespace std;
              int a,b;
              int main(){
                  cin>>a;
                  cin>>b;
                  cout<<a*b;
                  return 0;
              }//不用double的。
              
              • 1

              Information

              ID
              523
              Time
              1000ms
              Memory
              256MiB
              Difficulty
              1
              Tags
              # Submissions
              74
              Accepted
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              Uploaded By