2 solutions

  • 4
    @ 2024-1-26 9:25:49
    #include<bits/stdc++.h>
    using namespace std;
    int a1,a2,n;
    int ans;
    int main(){
    	cin>>a1>>a2>>n;
    	ans=a1;
    	for(int i=1;i<n;i++) ans+=(a2-a1);
    	cout<<ans<<"\n";
    	return 0;
    }
    
    • 1
      @ 2023-9-16 22:19:22
      #include <bits/stdc++.h>
      #define int long long
      using namespace std;
      int a[1005],n;
      signed main(){
      	cin>>a[1]>>a[2]>>n;
      	for(int i=3;i<=n;i++) a[i]=a[i-1]+a[2]-a[1];
      	cout<<a[n];
      	return 0;
      }
      
      • 1

      Information

      ID
      522
      Time
      1000ms
      Memory
      256MiB
      Difficulty
      1
      Tags
      # Submissions
      62
      Accepted
      41
      Uploaded By