#include
#include<iomanip>
using namespace std;
int main(){
 double x,a,y,b;
 cin>>x>>a>>y>>b;
 double z=(b*y-a*x)/(b-a);
 cout<<fixed<<setprecision(2);
 cout<<z;
 return 0;
}

代码

#include <bits/stdc++.h> using namespace std; int main(int argc, char **argv){ int x,a,y,b; scanf("%d %d %d %d",&x,&a,&y,&b); // printf("%.2f",1.0 * (y * b - (x * a)) / (b - a)); printf("%.2lf",double(y * b - (x * a)) / (b - a)); return 0; }

#include <bits/stdc++.h> using namespace std; int main(){ int a,b,c,d,e,f; cin>>a>>b>>c>>d; e=ab; f=cd; e=(f-e)/(d-b); cout<<e<<".00";

return 0;

}

#include <bits/stdc++.h>
using namespace std;
int main(){
    int x , y , a , b;
	scanf("%d %d %d %d", &x , &a , &y , &b);
	double o = (y * b - a * x) / (a - b);
	int h = -o;
	printf("%d.00", h); 
	
	return 0;
}

#include <bits/stdc++.h>
using namespace std;
int main(int argc, char **argv){
	int x,a,y,b;
	scanf("%d %d %d %d",&x,&a,&y,&b);
	// printf("%.2f",1.0 * (y * b - (x * a)) / (b - a));
	printf("%d.00",(y * b - (x * a)) / (b - a));
	return 0;
}

无语了，为啥数据是整数啊？

#include<iostream>
using namespace std;
int main(){
	long long cao,yuan,a,b,c,d;
	cin>>a>>b>>c>>d;
	cao=(c*d-(a*b))/(d-b);
	cout<<cao<<".00";
	return 0;
}

```
#include<iostream>
using namespace std;
int main(){
	long long cao,yuan,a,b,c,d;
	cin>>a>>b>>c>>d;
	cao=(c*d-(a*b))/(d-b);
	cout<<cao<<".00";
	return 0;
}

#include using namespace std; int main(){ long long cao,yuan,a,b,c,d; cin>>a>>b>>c>>d; cao=(cd-(ab))/(d-b); cout<<cao<<".00"; return 0; }

#include <bits/stdc++.h> using namespace std; int main(){ int a,b,c,d,e,f; cin>>a>>b>>c>>d; e=ab; f=cd; e=(f-e)/(d-b); cout<<e<<".00";

return 0;

}

#include<iostream>
#include<iomanip>
#include<cmath>
using namespace std;
int main(){
    double x,a,y,b;
    cin>>x>>a>>y>>b;
    cout<<fixed<<setprecision(2);
    int c=(b*y-a*x)/(b-a);
    cout<<(double)c;
    return 0;
}

#include<bits/stdc++.h>
using namespace std;
int main(){
	long long cao,yuan,a,b,c,d;
	cin>>a>>b>>c>>d;
	cao=(c*d-(a*b))/(d-b);
	cout<<cao<<".00";
	return 0;
}

#include<iostream>
#include<iomanip>.

using namespace std;
int main(){
int x,a,y,b;
   cin x>>a>>y>>b;
    double n=((x*a)-(y*b))*1.0/a-b;
   cout<<fixed<<setprecision(2)<<n;
   
   return 0;

}

#include<iostream>
#include<iomanip> 
using namespace std;
int main() {
    int x,a,y,b,p,q,r;
    cin>>x>>a>>y>>b;
	p=y*b-x*a;
    q=b-a;
    r=p/q;
	cout<<r<<".00";
	return 0;
}

#新题解

#include<iostream>
#include<iomanip> 
using namespace std;
int main() {
    double x,a,y,b,p,q,r;
    cin>>x>>a>>y>>b;
	p=y*b-x*a;
    q=b-a;
    r=p/q;
	cout<<fixed<<setprecision(2)<<r;
	return 0;
}