- C23panweiming's blog
- 圆周率的图像函数
- @ 2025-10-30 13:42:36
$y=((\operatorname{mod}(\operatorname{floor}(\pi*(10^{\operatorname{floor}(x)})),10)-\operatorname{mod}(\operatorname{floor}(\pi*(10^{\operatorname{floor}(x+1)})),10))/(\operatorname{floor}(x)-\operatorname{floor}(x+1)))*x+((\operatorname{floor}(x)*\operatorname{mod}(\operatorname{floor}(\pi*(10^{\operatorname{floor}(x+1)})),10)-\operatorname{floor}(x+1)*\operatorname{mod}(\operatorname{floor}(\pi*(10^{\operatorname{floor}(x)})),10))/(\operatorname{floor}(x)-\operatorname{floor}(x+1)))\ \left\{x\ge0\right\}$
圆周率
y=((\operatorname{mod}(\operatorname{floor}(\pi*(10^{\operatorname{floor}(x)})),10)-\operatorname{mod}(\operatorname{floor}(\pi*(10^{\operatorname{floor}(x+1)})),10))/(\operatorname{floor}(x)-\operatorname{floor}(x+1)))*x+((\operatorname{floor}(x)*\operatorname{mod}(\operatorname{floor}(\pi*(10^{\operatorname{floor}(x+1)})),10)-\operatorname{floor}(x+1)*\operatorname{mod}(\operatorname{floor}(\pi*(10^{\operatorname{floor}(x)})),10))/(\operatorname{floor}(x)-\operatorname{floor}(x+1)))\ \left\{x\ge0\right\}
万能
y=((\operatorname{mod}(\operatorname{floor}(a*(10^{\operatorname{floor}(x)})),10)-\operatorname{mod}(\operatorname{floor}(a*(10^{\operatorname{floor}(x+1)})),10))/(\operatorname{floor}(x)-\operatorname{floor}(x+1)))*x+(\operatorname{floor}(x+1)*\operatorname{mod}(\operatorname{floor}(a*(10^{\operatorname{floor}(x)})),10)-\operatorname{floor}(x)*\operatorname{mod}(\operatorname{floor}(a*(10^{\operatorname{floor}(x+1)})),10))\ \left\{x\ge0\right\}
 
      