#P6898. [ICPC 2014 WF] Metal Processing Plant

[ICPC 2014 WF] Metal Processing Plant

题目描述

Yulia works for a metal processing plant in Ekaterinburg. This plant processes ores mined in the Ural mountains, extracting precious metals such as chalcopyrite, platinum and gold from the ores. Every month the plant receives nn shipments of unprocessed ore. Yulia needs to partition these shipments into two groups based on their similarity. Then, each group is sent to one of two ore processing buildings of the plant.

To perform this partitioning, Yulia first calculates a numeric distance d(i,j)d(i, j) for each pair of shipments 1in1 \le i \le n and 1jn1 \le j \le n, where the smaller the distance, the more similar the shipments ii and jj are. For a subset S{1,,n}S \subseteq \{ 1, \ldots , n\} of shipments, she then defines the disparity DD of SS as the maximum distance between a pair of shipments in the subset, that is,

D(S)=maxi,jSd(i,j).D(S) = \max _{i, j \in S} d(i, j).

Yulia then partitions the shipments into two subsets AA and BB in such a way that the sum of their disparities D(A)+D(B)D(A) + D(B) is minimized. Your task is to help her find this partitioning.

输入格式

The input consists of a single test case. The first line contains an integer nn (1n2001 \le n \le 200) indicating the number of shipments. The following n1n - 1 lines contain the distances d(i,j)d(i,j). The ithi^{th} of these lines contains nin - i integers and the jthj^{th} integer of that line gives the value of d(i,i+j)d(i, i+j). The distances are symmetric, so d(j,i)=d(i,j)d(j, i) = d(i, j), and the distance of a shipment to itself is 00. All distances are integers between 00 and 10910^9 (inclusive).

输出格式

Display the minimum possible sum of disparities for partitioning the shipments into two groups.

5
4 5 0 2
1 3 7
2 0
4

4

7
1 10 5 5 5 5
5 10 5 5 5
100 100 5 5
10 5 5
98 99
3

15

提示

Time limit: 2000 ms, Memory limit: 1048576 kB.

International Collegiate Programming Contest (ACM-ICPC) World Finals 2014