2 solutions
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1
进食后人:
输出一行,为获得两个奖项的人的编号,按在科技创新奖获奖名单中的先后次序输出。
#include<bits/stdc++.h> using namespace std; int n,m; int a[100005],b[100005]; int find(int x){ int l=1,r=m; while(l<=r){ int mid=l+(r-l)/2; if(b[mid]==x){ return mid; } if(b[mid]>x){ r=mid-1; } if(b[mid]<x){ l=mid+1; } } return -1; } int main(){ cin>>n>>m; for(int i=1;i<=n;i++){ cin>>a[i]; t[i]=a[i]; } for(int i=1;i<=m;i++){ cin>>b[i]; } sort(b+1,b+m+1); for(int i=1;i<=n;i++){ if(find(a[i])!=-1){ cout<<a[i]<<" "; } } return 0; } -
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Information
- ID
- 563
- Time
- 1000ms
- Memory
- 125MiB
- Difficulty
- 2
- Tags
- # Submissions
- 49
- Accepted
- 15
- Uploaded By