#P10494. [USACO02FEB] Power Hungry Cows

    ID: 9880 Type: RemoteJudge 1000ms 512MiB Tried: 0 Accepted: 0 Difficulty: 5 Uploaded By: Tags>2002USACOO2优化启发式迭代加深搜索,IDA*

[USACO02FEB] Power Hungry Cows

题目描述

FJ's cows would like to be able to compute integer powers P (1 <= P <= 20,000) of numbers very quickly, but need your help. Because they're going to be computing powers of very large numbers, they can only keep around two work variables for intermediate results.

The first of those work variables is initialized to the number (denoted x) for which they are calculating the power; the other is initialized to 1. The cows can both multiply and divide any pair of the work variables and store the result in any work variable, but all results are stored as integers.

For example, if they want to compute x^31, one way to perform the calculation is:

Thus, x^31 can computed in six operations. Given the power to be computed and the the number of work variables, find the minimum number of operations to calculate the power.

输入格式

A single line with one integer: P.

输出格式

A single line with a single integer that is the minimum number of operations it requires to compute the pow

31
6