1 solutions
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1
#include<bits/stdc++.h> using namespace std; int a[105][105],b[105][105],n,m; double ans=0; int main(){ cin>>n>>m; for(int i=0;i<n;i++) for(int j=0;j<m;j++){ cin>>a[i][j]; b[j][i]=a[i][j]; } for(int i=0;i<m;i++){ for(int j=0;j<n;j++){ cout<<b[i][j]<<' '; } cout<<'\n'; } return 0; }
- 1
Information
- ID
- 6950
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 1
- Tags
- # Submissions
- 2
- Accepted
- 1
- Uploaded By