1 solutions
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1
#include<bits/stdc++.h> using namespace std; int n,a[105],ans[2010],cnt=0; int main(){ cin>>n; for(int i=0;i<n;i++){ cin>>a[i]; ans[i]=1; } a[n+1]=2000; for(int i=0;i<n;i++){ if(a[i+1]==a[i]){ ans[cnt]++; } else{ cnt++; } } sort(ans,ans+cnt); cout<<ans[cnt-1]; return 0; }
- 1
Information
- ID
- 6941
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 1
- Tags
- # Submissions
- 1
- Accepted
- 1
- Uploaded By