1 solutions

  • 1
    @ 2024-10-1 12:09:27
    #include<bits/stdc++.h>
    using namespace std;
    int n,a[105],ans[2010],cnt=0;
    int main(){
    	cin>>n;
    	for(int i=0;i<n;i++){
    		cin>>a[i];
    		ans[i]=1; 
    	}
    	a[n+1]=2000;
    	for(int i=0;i<n;i++){
    		if(a[i+1]==a[i]){
    			ans[cnt]++;
    		}
    		else{
    			cnt++;
    		}
    	}
    	sort(ans,ans+cnt);
    	cout<<ans[cnt-1];
    	return 0;
    }
    
    • 1

    Information

    ID
    6941
    Time
    1000ms
    Memory
    128MiB
    Difficulty
    1
    Tags
    # Submissions
    1
    Accepted
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