1 solutions
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0
纯模拟
#include<bits/stdc++.h> using namespace std; int a[5],cnt=0; int main(){ cin>>a[0]>>a[1]>>a[2]>>a[3]>>a[4]; for(int i=0;i<5;i++){ int k=a[i]/3; cnt+=a[i]-k*3; a[i]=k; if(i==0){ a[4]+=k; a[1]+=k; } else if(i==4){ a[3]+=k; a[0]+=k; } else{ a[i-1]+=k; a[i+1]+=k; } } cout<<a[0]<<' '<<a[1]<<' '<<a[2]<<' '<<a[3]<<' '<<a[4]<<'\n'; cout<<cnt; return 0; }
- 1
Information
- ID
- 6864
- Time
- 1000ms
- Memory
- 128MiB
- Difficulty
- 1
- Tags
- # Submissions
- 6
- Accepted
- 4
- Uploaded By