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尚未ac 求各路大佬求不/1000能ac的办法

#include<iostream>
#define int long long
using namespace std;
int s,n,d,zc[11],zl[11],dp[19198100];
signed main(){
	ios::sync_with_stdio(false);
	cin.tie(0);
	cout.tie(0);
	cin>>s>>n>>d;
	for(int i=1;i<=d;i++) cin>>zc[i]>>zl[i];
	while(n--){
		for(int i=1;i<=d;i++){
			for(int j=zc[i];j<=s;j++){
				dp[j]=max(dp[j],dp[j-zc[i]]+zl[i]);
			}
		}
		s+=dp[s];
	}
	cout<<s;
	return 0;
}